# SOLUTION: Find three consecutive odd integers such that three times the sum of the first and third is 18 greater than 4 times the second

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Find three consecutive odd integers such that three times the sum of the first and third is 18 greater than 4 times the second      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Numbers, consecutive odd/even, digits Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Numbers Word Problems Question 61402This question is from textbook An Incremental Development : Find three consecutive odd integers such that three times the sum of the first and third is 18 greater than 4 times the secondThis question is from textbook An Incremental Development Answer by funmath(2925)   (Show Source): You can put this solution on YOUR website!Find three consecutive odd integers such that three times the sum of the first and third is 18 greater than 4 times the second Odd numbers are 2 apart from each other: 1,3,5,7... 1,1+2,1+2+2,1+2+2+2 : Let the first number be: x Then the second will be: x+2 Then the third will be:x+2+2=x+4 "3 times" means 3* "sum" means + "is" means = "18 greater" means +18 "4 times" means 4* : 3(x+x+4)=4(x+2)+18 3(2x+4)=4x+8+18 6x+12=4x+26 6x-4x+12=4x-4x+26 2x+12=26 2x+12-12=26-12 2x=14 2x/2=14/2 x=7 The first number is: x=7 The second number is: x+2=7+2=9 The third number is: x+4=7+4=11 : Sanity Check, does 3 times the sum of the first and third number=4 time the second +18? 3(7+11)=4(9)+18 3(18)=36+18 54=54 Looks valid. : Happy Calculating!!!