SOLUTION: find the three consecutive odd integers such that four times the sum of the first and the second is seventeen more than seven times the third.
Algebra.Com
Question 610271: find the three consecutive odd integers such that four times the sum of the first and the second is seventeen more than seven times the third.
Answer by flame8855(424) (Show Source): You can put this solution on YOUR website!
x
x+2
x+4
4(x+x+2) = 17 +7(x+4)
8x+8 = 17 +7x+28
x = 37
so 37 , 39 41
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