SOLUTION: Please help me solve this question.
The square of a positive integer minus twice its consecutive integer is equal to 22. Find the integers.
Algebra.Com
Question 605293: Please help me solve this question.
The square of a positive integer minus twice its consecutive integer is equal to 22. Find the integers.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
x^2 - 2(x + 1) = 22 ___ x^2 - 2x - 2 = 22 ___ x^2 + 2x - 24 = 0
factoring ___ (x - 6 )(x + 4) = 0
RELATED QUESTIONS
Please help me solve this. The product of two consecutive integers is equal to ten times... (answered by mananth,MathTherapy)
A positive integer squared plus 6 times its consecutive integer is equal to 22. Find the... (answered by ikleyn,MathLover1)
find two consecutive positive integers such that the square of the second integer added... (answered by solver91311)
Please help me solve this question: twice the reciprocal of the larger positive even... (answered by ankor@dixie-net.com)
Five times of a positive integer less than twice its square by 3.Find the integer. solve... (answered by fractalier)
What is a positive integer squared plus 9 times its consecutive integer is equal to... (answered by CubeyThePenguin)
Five less than six times the largest of three consecutive positive integers is equal to... (answered by josgarithmetic,solver91311,MathTherapy)
the sum twice the square of a positive odd integer and its consecutive is 57. what are... (answered by mananth)
Hi please help me solve this word problem using integers.
The sum of two integers is... (answered by KMST)