SOLUTION: Find three consecutive positive intergers such that the product of the first and second intergers is 26 less than the product of the second and third.

Question 600102: Find three consecutive positive intergers such that the product of the first and second intergers is 26 less than the product of the second and third.
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Let the integers be n, n+1 and n+2
Given: product of the 1st and 2nd is 26 less than the product of the 2nd and 3rd
In equation form this is
n(n+1) = (n+1)(n+2) - 26
Solve for n:
n^2 + n = n^2 + 3n - 24
2n = 24
n = 12
Ans: 12, 13, 14
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