SOLUTION: The sum of two munbers is 21. Three times the smaller number is two less than twice the larger number. Find the two numbers.
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Question 59873: The sum of two munbers is 21. Three times the smaller number is two less than twice the larger number. Find the two numbers.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
X+Y=21 SO X=21-Y AND
3X=2Y-2
3(21-Y)=2Y-2
63-3Y=2Y-2
-3Y-2Y=-2-63
-5Y=-65
Y=-65/-5
Y=13
THEN X+13=21
X=21-13
X=8
PROOF
3*8=2*13-2
24=26-2
24=24
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