SOLUTION: there are three consecutive integers. the product of the first two plus the third integer is equal to 101

Question 586422: there are three consecutive integers. the product of the first two plus the third integer is equal to 101
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Let the integers be n, n+1, and n+2.
The product of the first two is
That plus the third integer is
If --> (subtracting 2 from both sides).
Now we can complete the square to solve the quadratic equation:
--> --> -->
The integers are 9, 10, and 11.

NOTE: There are other ways to solve that quadratic equation (factoring, the quadratic formula), but completing the square looked easier.
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