SOLUTION: Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers.

Question 586274: Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers.
----
1st: 2x-3
2nd: 2x-1
3rd: 2x+1
4th: 2x+3
------------------
Equation:
(2x-3)(2x-1) = (2x+1)(2x+3)-64
---
4x^2-8x+3 = 4x^2+8x+3 - 64
----
-16x = -64
x = 4
----
1st: 2x-3 = 5
2nd: 7
3rd: 9
4th: 11
--------------
Cheers,
Stan H.
============

RELATED QUESTIONS
Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less... (answered by josmiceli)

Find 4 consecutive odd integers where the product of the two smaller numbers less than... (answered by ankor@dixie-net.com)

Find 4 consecutive even integers where the product of the two smaller numbers is 72 less... (answered by RAY100)

Find 4 consecutive even integers where the product of the two smaller numbers is 56 less... (answered by Theo)

Find 4 consecutive even integers where the product of two smaller numbers is 56 less than (answered by josmiceli)

Find 4 consecutive odd integers if the product of the two smaller integers is 112 less... (answered by longjonsilver)

Find four consecutive odd integers if the product of the two smaller integers is 112 less (answered by Fombitz)

Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less... (answered by ankor@dixie-net.com)

Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less... (answered by checkley77)