SOLUTION: if the difference of an integer squared and twice the integer is 63, find the integer I set it up as x^2 -2x = 63 and then factored bu I don't think it is right

Question 584897: if the difference of an integer squared and twice the integer is 63, find the integer

I set it up as x^2 -2x = 63
and then factored bu I don't think it is right
Found 2 solutions by richwmiller, JBarnum:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!

x^2 -2x = 63
x^2 -2x - 63=0
(x+7)*(x-9)=0
x=9 and x=-7
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
right setup
you just didnt use the quadratic formula?

-9 and 7
-9 times 7 = -36
-9 plus 7 = -2
so:

x=9,-7
two possible answers

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