SOLUTION: The sum of two numbers is 41. Find the two numbers if the larger number is one less than twice the smaller number
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Question 584210: The sum of two numbers is 41. Find the two numbers if the larger number is one less than twice the smaller number
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
given:
a+b=41
a=(2b-1)
.
(2b-1)+b=41
3b-1=41
3b=42
b=14
a=27
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