SOLUTION: Four times the sum of the first and third of three consecutive integers is one less than seven times the middle integer. Find the integer.

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Question 57577: Four times the sum of the first and third of three consecutive integers is one less than seven times the middle integer. Find the integer.
Answer by phillv(13) About Me  (Show Source):
You can put this solution on YOUR website!
Let the first integer =X
Therefor the second integer =X+1
and the third integer = X+2
The resulting equation is: 4(X+(X+1))=7(X+2)-1
4(2X+1)=7X+14-1
8X+4=7X+13
8X-7X=13-4
X=9
The first integer is X=9
The second integer is X+1=10
The third integer is X+2=11