SOLUTION: Four times the sum of the first and third of three consecutive integers is one less than seven times the middle integer. Find the integer.

Question 57577: Four times the sum of the first and third of three consecutive integers is one less than seven times the middle integer. Find the integer.
Answer by phillv(13) (Show Source): You can put this solution on YOUR website!
Let the first integer =X
Therefor the second integer =X+1
and the third integer = X+2
The resulting equation is: 4(X+(X+1))=7(X+2)-1
4(2X+1)=7X+14-1
8X+4=7X+13
8X-7X=13-4
X=9
The first integer is X=9
The second integer is X+1=10
The third integer is X+2=11
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