SOLUTION: A 2 digit number exceeds twice the sum of its digits by 9, that number when reversed gives 8 times the sum of its digits. Find the number

Algebra.Com
Question 571992: A 2 digit number exceeds twice the sum of its digits by 9, that number when reversed gives 8 times the sum of its digits. Find the number
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let the 10's digit =
Let the 1's digit =
The number is
The number reversed is
--------------------------------
given:
(1)
(2)
--------------------------------------
(1)
(1)
(1)
and
(2)
(2)
(2)
(2)
Substitute this into (1)
(1)
(1)
(1)
(1)
(1)
and, since
(2)
(2)
(2)
The number is 27
check:



and


OK

RELATED QUESTIONS

The tens digit of a two-digit number exceeds twice its units digit by 1. If the digits... (answered by josgarithmetic)
The tens digit of a two-digit number exceeds twice its units digit by 1. If the digits... (answered by vleith)
a two digit number is such that when it is reversed the value of the number increases by... (answered by ankor@dixie-net.com)
A two digit number is 4 times the sum of its digits. If 27 is added to that number its... (answered by josmiceli)
A two digit number the sum of its two digits is three times of its units digit and its... (answered by Theo)
A number of two digits exceeds five times the sum of it a digits by 9 and its ten digit... (answered by solver91311)
1. the sum of the digits f a two-digit number is 11. when the digits are reversed, the... (answered by stanbon,jsmallt9)
the ones digit of a two-digit number is twice the tens digit. If the number exceeds the... (answered by ankor@dixie-net.com)
The value of a two-digit number is twice as large as the sum of its digits. If the... (answered by stanbon)