SOLUTION: find the triple of consecutive integers such that 11 times the largest of the integers is 46 more than the product of the other two

SOLUTION: find the triple of consecutive integers such that 11 times the largest of the integers is 46 more than the product of the other two

Algebra.Com

Question 567957: find the triple of consecutive integers such that 11 times the largest of the integers is 46 more than the product of the other two
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Call the integers , , and
given:

complete the square:

also,

------------
If the numbers are:

OK
If the numbers are:

OK
The consecutive integers can be:
6,7, and 8
or
4,5, and 6
RELATED QUESTIONS
find three consecutive integers such that the product of the two smaller inters is 2 more (answered by EMStelley)

find three consecutive integers such that the product of the two smaller inters is 2 more (answered by Earlsdon)

Help I hate setting up word problems I just cant master it the question is: find four... (answered by checkley77)

Find three consecutive integers such that the product of the two largest is 20 more than... (answered by CubeyThePenguin)

Find three positive consecutive integers such that the product of the smallest and the... (answered by Alan3354)

find the smallest of three consecutive positive integers such that the product of two... (answered by ad_alta)

Find 3 consecutive integers such that the product of the smallest and largest integers is (answered by CubeyThePenguin)

What is the largest of 3 consecutive positive even integers such that the product of the... (answered by LinnW)

how to solve the problem find 4 consecutive integers such that twice the sum of the two... (answered by ReadingBoosters)