SOLUTION: pls help me understand this problem: Find a number that is 68 greater than three times its opposite.

Question 56638This question is from textbook Algebra Structure and Method .Book1
: pls help me understand this problem: Find a number that is 68 greater than three times its opposite. This question is from textbook Algebra Structure and Method .Book1

Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Find a number that is 68 greater than three times its opposite.
Let a number be:x
It's opposite would be:-x
3 times means: 3*
68 greater than means: +68
is means: =
The equation:
x=3(-x)+68
x=-3x+68
3x+x=3x-3x+68
4x=68
4x/4=68/4
x=17
Happy Calculating!!!
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