SOLUTION: The product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the three integers.
let 2x+1 = 1st odd integer
2x+3 = 2nd odd
Algebra.Com
Question 566037: The product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the three integers.
let 2x+1 = 1st odd integer
2x+3 = 2nd odd integer
2x+5 = 3rd odd integer
Please help me in completing the solution! THANKS :)
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
you can also work it out this way
let the consequtive odd numbers be x,x+2,x+4
x(x+2)=(x+4)^2-58
x^2+2x=x^2+8x+16-58
x^2 cancels off
2x-8x=16-58
-6x=-42
/6
x=7
the numbers are 7,9,11
CHECK
7*9=63
11^2=121
121-58=63
RELATED QUESTIONS
The product of two consecutive odd integers is 58 less than the square of the next... (answered by mananth)
4. The Product of two consecutive odd integers is 58 less than the square of the next... (answered by josgarithmetic)
The product of two consecutive odd integers is 58 less than the square of the next... (answered by macston)
The product of two consecutive odd integers is 10 more than the square of the smaller... (answered by stanbon,drj)
The product of two consecutive odd integers is twenty-two more than the square of the... (answered by ikleyn)
The product of two consecutive odd integer is 1 less than 4 times their sum find the two... (answered by checkley77,ankor@dixie-net.com)
The product of two consecutive positive odd integers is 38 less than the square of the... (answered by ad_alta)
The product of two consecutive odd integers is 22 less than the square of the greater... (answered by algebrahouse.com)
The product of two consecutive odd integers is nine less than four times the opposite of... (answered by nyc_function)