SOLUTION: what are four consecutive odd integers who's sum is 192

SOLUTION: what are four consecutive odd integers who's sum is 192

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Question 565153: what are four consecutive odd integers who's sum is 192
Answer by ad_alta(240) (Show Source): You can put this solution on YOUR website!
Let 'n' be the smallest integer. Then n+(n+2)+(n+4)+(n+6)=192, so 4n+12=192. Therefore n=45. The integers are 45, 47, 49, 51.
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