SOLUTION: The area of a rectangle is 7in^2 , and its perimeter is 16in . Find its dimensions

Question 564842: The area of a rectangle is 7in^2 , and its perimeter is 16in . Find its dimensions
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
The area of a rectangle is 7in^2 , and its perimeter is 16in . Find its dimensions
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Area = l*w = 7 -> w = 7/l
Perimeter = 2(l+w) = 16 -> l + w = 8 -> l + 7/l = 8
Solve for l:
l^2 - 8l + 7 = 0
Factor:
(l-7)(l-1) = 0
This gives 2 possible answers, l=7 and l=1
If the long dimension is l, we have length = 7 in., width = 1 in.
If the long dimension is w, we have length = 1 in., width = 7 in.
In either case, the dimensions are 7 in. and 1 in.
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