SOLUTION: The difference of two positive numbers is 4 and the sum of their squares is 40. Find the numbers
Algebra.Com
Question 564841: The difference of two positive numbers is 4 and the sum of their squares is 40. Find the numbers
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Let the two numbers = a and b
Given:
a - b = 4 -> a = b + 4
a^2 + b^2 = 40
(b+4)^2 + b^2 = 40
Solve for b:
b^2 + 8b + 16 + b^2 - 40 = 0
2(b^2 + 4b - 12) = 0
Factoring gives
(b-2)(b+6) = 0
Since the numbers are positive, we have b=2
Therefore the two numbers are 2 and 6
RELATED QUESTIONS
the difference of 2 positive numbers is 4 and the sum of their squares is... (answered by xdragonfight)
the difference of two positive numbers is 4 and the sum of their squares is 80. Find the... (answered by ewatrrr)
The difference of two positive numbers is 2 and the sum of their squares is 74. Find the... (answered by ankor@dixie-net.com)
The difference of two positive numbers is 6 and the sum of their squares is 90. Find the... (answered by solver91311)
The difference of two positive numbers is 3 and the sum of their squares is 45. Find the... (answered by stanbon)
The difference of two positive numbers is 5 and the sum of their squares is 125. Find the (answered by sofiyac)
The difference of two positive numbers is 9 and the sum of their squares is 101. Find the (answered by jim_thompson5910)
The difference of two positive numbers is 1 and the sum of their squares is 61. Find the... (answered by kevwill)
The difference of two positive numbers is 3 and their difference of their squares is 69.... (answered by Edwin McCravy)