SOLUTION: find four consecutive integers such that the sum of the first three is 54 more than the fourth.

Question 563489: find four consecutive integers such that the sum of the first three is 54 more than the fourth.
Found 3 solutions by mananth, josmiceli, Maths68:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
Let the consequtive numbers be x,x+1,x+2,x+3
x+x+1+x+2=x+3+54
3x+3=x+57
3x-x=57-3
2x=54
/2
x=27
27,28,29,30

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Call the integers , , , and
given:

The integers are 27,28,29, and 30
check:

OK
Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!
Let
First integer =
Second integer=
Third integer =
Fourth integer =

Given
=======
The sum of the first three is 54 more than the fourth.

Divide by 2 both sides of the above equation

First integer = ==
Second integer===
Third integer = ==
Fourth integer = ==

Check
======
The sum of the first three is 54 more than the fourth.

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