SOLUTION: The Length of a rectangular room is 2 feet longer than twice the width. If the room's perimeter is 136 feet, what are the room's dimensions?

Question 559974: The Length of a rectangular room is 2 feet longer than twice the width. If the room's perimeter is 136 feet, what are the room's dimensions?
Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Perimeter = 136
Length (2x+2)
Width =x ft

Perimeter = 2(2x+2)+x)
Perimeter = 2(2x+2 +x)
Perimeter =4x+4+2x
136=6x+4
136-=6x
136-4=6x
132=6x
x=22 ft Width
Length= 46
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Given:
(1) ft
also
The formula for Perimeter is

Given:
ft
(2)
--------------------
(1)
(1)
Subtract (1) from (2)
(2)
(1)

and, since
(1)
(1)
(1)
(1)
(1)
(1)
The room's dimensions are 22' x 46'
check:

OK
(1)
(1)
(1)
(1)
OK
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