SOLUTION: One number is 7 less than a second number. Twice the second number is 4 less than 5 times the first. Find the smaller of two numbers.

Question 534261: One number is 7 less than a second number. Twice the second number is 4 less than 5 times the first. Find the smaller of two numbers.
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
Define the two numbers as
x
x+7
.
2(x+7) + 4 = 5x
2x + 14 +4 = 5x
18 = 3x
3x = 18
x = 6
.
x+7 = 13
.
One number is 7 less than another.
6 is 7 less than 13.
Correct.
.
Twice the second number = 2*13 = 26
Is 26 4 less than 5 times the first number.
5*6 = 30
30-26 = 4
Correct.
.
Re-read the question to determine what the answer needs to be.
.
Answer: The smaller of the two numbers is 6.
.
Done.
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