SOLUTION: find four consecutive odd intergers such that twice the sum of the first two numbers is eight more than the sum of the last two numbers

SOLUTION: find four consecutive odd intergers such that twice the sum of the first two numbers is eight more than the sum of the last two numbers

Algebra.Com

Question 53020: find four consecutive odd intergers such that twice the sum of the first two numbers is eight more than the sum of the last two numbers
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
2(X+X+2)=(X+4)+(X+6)+8 OR 2X+2X+4=2X+10+8 OR 4X-2X=18-4 OR 2X=14 THEN X=7
SO THE NUMBERS ARE 7,9,11 & 13
PROOF 2(7+9)=11+13+8 OR 2*16=32 OR 32=32
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