SOLUTION: The sum of the squares of two integers is 80 and one number is twice the other. What are the numbers?

Question 529769: The sum of the squares of two integers is 80 and one number is twice the other. What are the numbers?
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
x^2 + y^2 = 80
x = 2y
(2y)^2 + y^2 = 80
4y^2 + y^2 = 80
5y^2 = 80
y^2 = 16
y=4 [or -4]
So x = 2(4)
x = 8 [or -8]
4 and 8 are your answers. But if you think about it, -4 and -8 work too. Not sure how advanced your class is, but yeah, think about it. -4^2 + -8^2 = 16 + 64 = 80 and -4 * 2 = -8.
RELATED QUESTIONS
The sum of two numbers is 121. The sum of twice one of the numbers and three times the... (answered by t0hierry)

The sum of a 2 integers is 23. Twice one number is 74 less than the other number. What... (answered by josgarithmetic)

one number is twice the other. the sum of the numbers is 246. what are the two... (answered by ReadingBoosters)

the sum of two numbers is 63. if one number is twice the other, what are the numbers? (answered by Alan3354)

the sum of two numbers is 63. If one number is twice the other, what are the numbers? (answered by Alan3354)

One number is 6 less than the other. The sum of the squares of these two numbers is 20.... (answered by Fombitz)

Jack is thinking of two positive numbers, one of them is 4 more than the other and the... (answered by algebrahouse.com)

A number is twice another number and the sum of their squares is 80. Find the... (answered by ikleyn)

The sum of the squares of two consecutive integers is thirty one less.than twice the... (answered by solver91311)