SOLUTION: The product of two consecutive integers is 47 more than the next consecutive integer. Find the two integers.

SOLUTION: The product of two consecutive integers is 47 more than the next consecutive integer. Find the two integers.

Algebra.Com

Question 527402: The product of two consecutive integers is 47 more than the next consecutive integer. Find the two integers.

Answer by sextoned(4) (Show Source): You can put this solution on YOUR website!
x(x+1) = 47+(x+2)
x^2 + x = 49 +x
subtract x from both sides leaves us with
x^2 = 49 therefore x=7 and x+1 = 8
7*8 =56
56-47=9
RELATED QUESTIONS
The product of two consecutive odd integers is 10 more than the square of the smaller... (answered by stanbon,drj)

The product of two consecutive odd integers is five more than six times the lesser... (answered by Fombitz)

The product of two consecutive positive integers is 27 more than five times the larger... (answered by TimothyLamb)

the product of two consecutive positive integers is 52 more than 8 times the larger... (answered by hkwu)

The product of two consecutive positive integers is 22 more than eight times the larger... (answered by amarjeeth123)

The product of two consecutive positive integers is 12 more than 5 times the smaller... (answered by macston)

The product of two positive consecutive integers is 24 more than nine times the larger... (answered by CubeyThePenguin)

The product of two consecutive positive integers is 27 more than five times the larger... (answered by CubeyThePenguin)

4. The Product of two consecutive odd integers is 58 less than the square of the next... (answered by josgarithmetic)