SOLUTION: find two consecutive even integers whose sum is 217. I have no idea what to do on that problem. Thanks if someone can help.

Question 52621: find two consecutive even integers whose sum is 217.
I have no idea what to do on that problem.
Thanks if someone can help.
Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find two consecutive even integers whose sum is 217.
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Even numbers are always a multiple of 2.
Let the 1st number be "2x"
The next consecutive even number is "2x+2"
EQUATION:
2x+2x+2=217
4x+2=217
4x=215
x is not an integer.
WHY?
The sum of two even integers must be even; it cannot be 217.
Cheers,
Stan H.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
x+(x+2)=217 or 2x+2=217 or 2x=217-2 or 2x=215 or x=107.5 then x+2=107.5+2=109.5
proof 107.5+109.5=217 opr 217=217
107.5 & 109.5 are not even integers???????
two even integers added will result in an even interger. 217 is not one of them.
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