SOLUTION: The perimeter of a rectangle is 164 ft. The length is 20 feet less than twice the width. Find the dimensions of the rectangle.

Question 525516: The perimeter of a rectangle is 164 ft. The length is 20 feet less than twice the width. Find the dimensions of the rectangle.
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 164 ft. The length is 20 feet less than twice the width. Find the dimensions of the rectangle.
P=164 ft.
l=2w-20
w=?
l=?
p= 2l + 2w
164=2(2w-20)+2w
164=4w-40+2w
164=6w-40
164+40=6w
204=6w
204/6=w
34=w
Dimension of the perimeter
Perimeter = 164 ft
Width = 34 ft
length = 2w-20 = 2(34)-20 = 68-20=48ft
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