SOLUTION: I always have problems with these word problems: Find three consecutive even numbers so that the sum of the first and third numbers is 22 less than three times the second number. T

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Question 525: I always have problems with these word problems: Find three consecutive even numbers so that the sum of the first and third numbers is 22 less than three times the second number. This one is hard, I would love it if you helped me out on this please and thank you!
Kelsie

Answer by arden42(16) About Me  (Show Source):
You can put this solution on YOUR website!
Well, first we need to assign letters to each of the numbers. x, y and z will do.
Now, if they are consecutive even numbers, then we know that x is 2 less than y, and y is 2 less than z:
x+=+y-2
y+=+z-2
We'll rearrange the second one to be consistent:
z+=+y+%2B+2
Now for the rest of the question. The first number plus the third number is 22 less than the second number multiplied by 3:
x+%2B+z+=+3y+-+22
To work out the numbers, we will need to substitute the first 2 equations into the third, like this:
%28y+-+2%29+%2B+%28y+%2B+2%29+=+3y-22
Expanding the brackets gives:
2y+=+3y-22
Adding 22 to both sides, and taking away 2y from both sides:
22=y
So the middle number is 22. Since the other numbers are the even numbers either side of it, the final answer is:
The 3 numbers are 20, 22 and 24.