SOLUTION: The distance in feet that an object falls in a vacuum is given by
s(t)= 16t^2, where t represents the time in seconds. a) Find :
s(2+h) - s(2)/h ?
b) what happens when h t
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-> SOLUTION: The distance in feet that an object falls in a vacuum is given by
s(t)= 16t^2, where t represents the time in seconds. a) Find :
s(2+h) - s(2)/h ?
b) what happens when h t
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Question 524957: The distance in feet that an object falls in a vacuum is given by
s(t)= 16t^2, where t represents the time in seconds. a) Find :
s(2+h) - s(2)/h ?
b) what happens when h tends to 0 ? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The distance in feet that an object falls in a vacuum is given by
s(t)= 16t^2, where t represents the time in seconds.
a) Find
s(2+h) - s(2)/h
=
=
=
=
= 64 + 16h
--------------
b) what happens when h tends to 0 ?
s(2+h) - s(2)/h approaches 64
