SOLUTION: find three consecutive integers that the sum of the first and twice the second is 92 minus three times the third.

Question 524452: find three consecutive integers that the sum of the first and twice the second is 92 minus three times the third.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find three consecutive integers that the sum of the first and twice the second is 92 minus three times the third.
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1st: x-1
2nd: x
3rd: x+1
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Equation:
x-1 + 2x = 92-3(x+1)
3x-1 = 92-3x-3
6x = 90
x = 15
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1st: 14
2nd: 15
3rd: 16
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Cheers,
Stan H.
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