SOLUTION: the sum of three numbers is 237. the second number is 9 less than two times the first number. the third number is 6 more than three times the first number. what are the three numbe

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 Question 523638: the sum of three numbers is 237. the second number is 9 less than two times the first number. the third number is 6 more than three times the first number. what are the three numbers?Found 2 solutions by oberobic, stanbon:Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!x + y + z = 237 . y = 2x -9 . z = 3x +6 . substitute . x +2x-9 +3x+6 = 237 . 6x -3 = 237 . 6x = 240 . x = 40 . substitute . y = 2x -9 y = 2*40 -9 y = 71 . z = 3x +6 z = 3*40 +6 z = 126 . Check the sum . 40 + 71 + 126 = 237 . Answer: The three numbers are 40, 71, and 126. . Done. Answer by stanbon(57347)   (Show Source): You can put this solution on YOUR website!the sum of three numbers is 237. the second number is 9 less than two times the first number. the third number is 6 more than three times the first number. what are the three numbers? ------ Equations: x + y + z = 237 y = 2x-9 z = 3x+6 --------------- Substitute for "y" and for "x"; then solve for "x": x + (2x-9) + (3x+6) = 237 --- 6x - 3 = 237 6x = 240 x = 40 ----- y = 2x-9 = 80-9 = 71 ----- z = 3x+6 = 126 ======================= Cheers, Stan H. =======================