SOLUTION: the sum of three numbers is 237. the second number is 9 less than two times the first number. the third number is 6 more than three times the first number. what are the three numbe

Question 523638: the sum of three numbers is 237. the second number is 9 less than two times the first number. the third number is 6 more than three times the first number. what are the three numbers?
Found 2 solutions by oberobic, stanbon:
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
x + y + z = 237
.
y = 2x -9
.
z = 3x +6
.
substitute
.
x +2x-9 +3x+6 = 237
.
6x -3 = 237
.
6x = 240
.
x = 40
.
substitute
.
y = 2x -9
y = 2*40 -9
y = 71
.
z = 3x +6
z = 3*40 +6
z = 126
.
Check the sum
.
40 + 71 + 126 = 237
.
Answer: The three numbers are 40, 71, and 126.
.
Done.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the sum of three numbers is 237. the second number is 9 less than two times the first number. the third number is 6 more than three times the first number. what are the three numbers?
------
Equations:
x + y + z = 237
y = 2x-9
z = 3x+6
---------------
Substitute for "y" and for "x"; then solve for "x":
x + (2x-9) + (3x+6) = 237
---
6x - 3 = 237
6x = 240
x = 40
-----
y = 2x-9 = 80-9 = 71
-----
z = 3x+6 = 126
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Cheers,
Stan H.
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