SOLUTION: Find three consecutive odd intergers such that the sum of the first, two times the second, and three times the third is 82. this has me stumped

SOLUTION: Find three consecutive odd intergers such that the sum of the first, two times the second, and three times the third is 82. this has me stumped

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Question 52170: Find three consecutive odd intergers such that the sum of the first, two times the second, and three times the third is 82. this has me stumped

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
THE THREE NUMBERS ARE X,X+2 & X+4 SO X+2(X+2)+3(X+4)=82 THUS X+2X+4+3X+12=82 OR
6X+16=82 0R 6X=82-16 OR 6X=66 OR X=66/6 OR X=11 THUS THE OTHER TWO NUMBERS ARE
11+2=13 & 11+4=15
PROOF 11+2*13+3*15=82 OR 11+26+45=82 OR 82=82
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