SOLUTION: All the positive integers with an initial digit of 2 are written down in succession. What is the 1978th digit thus written?

Question 520170: All the positive integers with an initial digit of 2 are written down in succession. What is the 1978th digit thus written?
Found 2 solutions by solver91311, josmiceli:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

2 is the first one, then 20 through 29 are the next 10, then 200 through 299 are the next 100, then 2000 through 2999 are the next 1000. 1 + 10 + 100 + 1000 = 1111. 1978 minus 1111 is 867, so we need 867 more: 20000 through 20866 (only 866 because of zero based count)

John

My calculator said it, I believe it, that settles it

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
2 = 1 integer
20 - 29 = 10 integers
200 - 299 = 100 integers
2000 - 2999 = 1000 integers
So far:
integers

20000 - 20866 = 867 integers
The 1978th integer is 20866
RELATED QUESTIONS
what is the sum of all positive two-digit integers with exactly five positive integral... (answered by ikleyn)
Beginning with 1, all the postive intgers are written successively, beginning... (answered by josmiceli)
All 4-digit integers with the same digits as the number 2011 (two 1�s, 0, and 2) are... (answered by richard1234,Edwin McCravy)
The positive integers, starting with 1, are written in order 123456789101112.... The... (answered by Targetweek)
Find the sum of all even five-digit positive integers that are multiple of... (answered by Edwin McCravy)
What is the sum of all the positive 3-digit whole numbers with even digits... (answered by robertb)
if an integer is randomly chosen from the first 50 positive integers, what is the... (answered by luke94,jim_thompson5910)
if an integer is randomly chosen from the first 50 positive integers, what is the... (answered by CubeyThePenguin)
All the odd numbers from 51 to 5001 are written. What is the total numbers of digit... (answered by AnlytcPhil,Edwin McCravy)