SOLUTION: The product of 2 consecutive even integers is 28 more than 5 times the smaller number. Find the 2 numbers (they are positive).
Algebra.Com
Question 519624: The product of 2 consecutive even integers is 28 more than 5 times the smaller number. Find the 2 numbers (they are positive).
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
Two consecutive even numbers can be defined as:
x
x+2
.
x*(x+2) = 5*x +28
.
x^2 +2x =5x + 28
.
x^2 -3x -28 = 0
.
factor
.
(x-7)(x+4) = 0
.
x = 7 or x = -4
.
So, there are no two consecutive even integers whose product is 28 more than 5 times the smaller.
.
Done.
RELATED QUESTIONS
1. The product of two consecutive odd numbers is 10 more than the square of the smaller... (answered by jojo14344)
The product of two consecutive odd integers is 6 more than 5 times the smaller number,... (answered by mananth)
The product of two consecutive even integers is 30 more than 9 times the smaller integer. (answered by josmiceli)
The product of two consecutive even integers is 4 more than 5 times the smaller of the... (answered by scott8148)
The smaller of two consecutive even integers is 2 more than twice the larger. Find the... (answered by checkley77)
the larger of two consecutive even integers is 2 more than twice the smaller. find the... (answered by checkley77)
the product of two consecutive even numbers is 12 more than the square of the smaller... (answered by Alan3354)
The product of two consecutive even integers is 76 more than 2 times their sum. Find... (answered by user_dude2008)
1.one number is 11 more than another number. find the two numbers if three times the... (answered by MathLover1)