# SOLUTION: find two consecutive whole numbers such that the sum of their square is 41.

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 Click here to see ALL problems on Numbers Word Problems Question 515261: find two consecutive whole numbers such that the sum of their square is 41.Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Let One number = x Other number = x+1 sum of their square = 41 x^2+(x+1)^=41 x^2+x^2+2x+1=41 2x^2+2x+1-41=0 2x^2+2x-40=0 2*(x^2+x-20)=0 2*(x^2+x-20)/2=0/2 x^2+x-20=0 x^2-4x+5x-20=0 x(x-4)+5(x-4)=0 (x-4)(x+5)=0 x-4=0 or x+5=o x=4 or x=-5 One number = x = 4 Other number = x+1 = 4+1 = 5 4^2+5^2=41 16+25=41 41=41