SOLUTION: A chemist work on a new project needs 12liters of 50% acid solution, The stockroom only has 40% and 70% solutions. how much of each solution should be mixed together to form 12 lit

Question 509905: A chemist work on a new project needs 12liters of 50% acid solution, The stockroom only has 40% and 70% solutions. how much of each solution should be mixed together to form 12 liters of a 50% solution.
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Solution A
Concentration = 40%=0.4
Amount = x
=======================
Solution B
Concentration = 70%=0.7
Amount = 12-x
==========================
Resultant Solution
Concentration = 50%=0.5
Amount = 12 liters
========================================
(Concentration of A * Amount of A)+(Concentration of B * Amount of B)=(Concentration of Resultant * Amount of Resultant)
==========================================
0.4x+0.7(12-x)=0.5*12
0.4x+8.4-0.7x=6
-0.3x=6-8.4
-0.3x=-2.4
Divide by -0.3 both sides
-0.3x/-0.3=-2.4/-0.3
x=8
==========================================
Amount of solution A = x = 8 liters
Amount of solution B = 12-x = 12-8 = 4 liters
Conclusion
==========
chemist needs to mix 8 liters of 40% and 4 liters of 70% solutions to get 12 liters of a 50% solution.

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