# SOLUTION: how do i solve this problem,- The hundreds digit of a three-digit number is 2 more than the units digit. The digits of the original three-digit number are reversed, and the result

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 Question 507904: how do i solve this problem,- The hundreds digit of a three-digit number is 2 more than the units digit. The digits of the original three-digit number are reversed, and the result is subtracted from the original three-digit number. What is the units digit of the result? Describe anything interesting you discover finding the solution. You need to try this out on at least three 3-digit numbers of your choosing.Answer by josmiceli(9692)   (Show Source): You can put this solution on YOUR website!Call the digits a,b, and c The number is abc given: a = c + 2 abc - cba The units digit will be c - (c + 2) , but to do this, you have to carry 10 over to the c, and you have 10 + c - (c + 2) = 8 check: abc = 553 cba = 355 553 - 355 = 198 --------------- abc = 917 cba = 719 917 - 719 = 198 --------------- abc = 391 cba = 193 391 - 193 = 198 --------------- The result is always 198