SOLUTION: The sum of the digits of a certain two certain numbers is 11 when reverse it's digits you increase the number number 45.

Question 507740: The sum of the digits of a certain two certain numbers is 11 when reverse it's digits you increase the number number 45.
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
x + y = 11
x = 11-y
.
10y + x = 10x+y+45
.
10y + 11 -y = 10(11-y) + y + 45
.
10y +11 -y = 110 -10y + y + 45
.
9y + 11 = 155 -9y
.
18y = 144
.
y = 144/18
.
y = 8
.
x = 11-8
.
x = 3
.
So the original number was 38.
.
If you reverse the digits, you have 83.
.
38 + 45 = 83
.
Correct.
.
Answer: The original number was 38.
.
Done.
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