SOLUTION: the sum of three times one number and seven times another is 62. the difference between the numbers is 4. what are the numbers?

Question 500750: the sum of three times one number and seven times another is 62. the difference between the numbers is 4. what are the numbers?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
x = one number
y = another number
.
3x + 7y = 62
.
the difference between x & y = 4
x - y = 4
x = y +4
.
substitute for x
.
3(y+4) +7y = 62
.
3y +12 +7y = 62
10y = 50
y = 5
.
substitute y = 5 to find x
.
x = y+4
x = 5+4
x = 9
.
Always check your answer.
.
3(9) + 7(5) = ?
27 + 35 = 62
Correct.
.
Answer: The two numbers are 5 and 9.
.
Done.
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