SOLUTION: One-fifth of sum of two consecutive integers is 64 less than the smaller integer.
Find the smaller of the two integers
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Question 489141: One-fifth of sum of two consecutive integers is 64 less than the smaller integer.
Find the smaller of the two integers
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
1/5(n+(n+1)=n-64
1/5(2n+1)=n-64
2n+1=5n-320
321=3n
n=107
n+1=108
The integers are 107 and 108..
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