One number Y is 3 times a first number X. Y = 3X A third number Z is 100 more than the first number X. Z = X + 100 The sum of the three numbers is 585 X + Y + Z = 585 Can you solve this system of equation: ìY = 3X íZ = X + 100 îX + Y + Z = 585 If not post again asking how. The solution is X = 97, Y = 291, Z = 197 Checking in the words, not the equations: 291 is 3 times 97. 197 is 100 more than the 97. The sum of 97, 291 and 197 is 585. That checks. Edwin