SOLUTION: the sum of two numbers is 40. the difference of twice the first number and the second is 11. what are the numbers?
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Question 487212: the sum of two numbers is 40. the difference of twice the first number and the second is 11. what are the numbers?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
m+n=40
2m-n=11
2m-11=n
m+2m-11=40
3m=51
m=17
n=23..
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