# SOLUTION: the sum of three consecutive integers is equal to 13 more than twice the smallest integer

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 Question 485261: the sum of three consecutive integers is equal to 13 more than twice the smallest integerFound 2 solutions by mananth, MathTherapy:Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!x, x+1, x+2 are the integers x+x+1+x+2= 2x+9 3x+3=2x+9 3x-2x=9-3 x=6 6,7,8 are the integers Answer by MathTherapy(1430)   (Show Source): You can put this solution on YOUR website!the sum of three consecutive integers is equal to 13 more than twice the smallest integer Let the smallest number be S Then the middle and largest numbers are: S + 1, and S + 2, respectively Since their sum is equal to 13 more than twice the smallest integer, then we’ll have: S + S + 1 + S + 2 = 2S + 13 3S + 3 = 2S + 13 S = 10 Since smallest = 10, then the three numbers are: ---------- Check ---------- I’ll leave the check for you to do. Send comments and “thank-yous” to MathMadEzy@aol.com