SOLUTION: the sum of three consecutive integers is equal to 13 more than twice the smallest integer

Question 485261: the sum of three consecutive integers is equal to 13 more than twice the smallest integer
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x, x+1, x+2 are the integers

x+x+1+x+2= 2x+9
3x+3=2x+9
3x-2x=9-3
x=6
6,7,8 are the integers
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
the sum of three consecutive integers is equal to 13 more than twice the smallest integer

Let the smallest number be S
Then the middle and largest numbers are: S + 1, and S + 2, respectively
Since their sum is equal to 13 more than twice the smallest integer, then we�ll have:

S + S + 1 + S + 2 = 2S + 13

3S + 3 = 2S + 13
S = 10
Since smallest = 10, then the three numbers are:
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Check
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I�ll leave the check for you to do.

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