Suppose z varies directly as x and y and inversely as w, and z =8 when x =6, y =5 and w =10. Find z when x =3, y =4 and w = 5.
FORMULA:
product of "directly" or "jointly" variables
"Varies as" variable = k* --------------------------------------------
product of "inversely" variables
The "varies as" variable is z, so write:
z = k*-----
The "directly variables" are x and y, so write them on the top:
xy
z = k*-----
There is just one "inversely variable", w, so write it on the bottom:
xy
z = k*-----
w
Now we're ready to substitute the numbers for all the letters except the
constant k from this: "z =8 when x =6, y =5 and w =10". Substituting:
6*5
8 = k*-----
10
Solve for k:
30
8 = k*-----
10
8 = k*3
8
--- = k
3
Now go back to this equation:
xy
z = k*-----
w
and substitute 3/8 for the constant k.
3 xy
z = ---*----
8 w
or
3xy
z = -----
8w
Now we substitute in x =3, y =4 and w = 5, to find z:
3(3)(4)
z = --------
8(5)
Then finish it up:
36
z = ----
40
Reduce the fraction:
9
z = ----
10
The answer is 9/10.
[In many problems one of the types of variables "directly", "jointly",
or "inversely" variables are missing, in which case you put 1 for them.]
Edwin