SOLUTION: I am currently working on my summer math packet and I am stuck on this word problem "If 5 times the square of an integer is decreased by 32 times the number the result is 21. Find

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Question 478045: I am currently working on my summer math packet and I am stuck on this word problem "If 5 times the square of an integer is decreased by 32 times the number the result is 21. Find the number."
Found 2 solutions by mananth, MathLover1:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
let the integer be x
5x^2-32x=21
5x^2-32x-21=0
Find the roots of the equation by quadratic formula

a= 5 b= -32 c= -21

b^2-4ac= 1024 - 420
b^2-4ac= 1444
= 38



x1=( 32 + 38 )/ 10
x1= 7
x2=( 32 -38 ) / 10
x2= -0.6
Ignore -0.6

7 is the number


Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

let's the number be
If 5 times the square of an integer
is decreased by times the number
the result is ...->....solve quadratic
...use quadratic formula

Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=5, b=-32, and c=-21




Negate -32 to get 32




Square -32 to get 1024 (note: remember when you square -32, you must square the negative as well. This is because .)




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 5 to get 10


So now the expression breaks down into two parts


or


Lets look at the first part:





Add the terms in the numerator

Divide


So one answer is






Now lets look at the second part:





Subtract the terms in the numerator

Divide


So another answer is




So our solutions are:

or




check our solutions:





or








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