SOLUTION: Find two consecutive odd integers so that the square of the larger exceeds their product by 34.
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Question 475656: Find two consecutive odd integers so that the square of the larger exceeds their product by 34.
Found 2 solutions by htmentor, Alan3354:
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Find two consecutive odd integers so that the square of the larger exceeds their product by 34.
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Let n and n+2 be the two consecutive odd integers.
The problem in equation form is:
(n+2)^2 = n(n+2) + 34
square of the larger = their product + 34
Simplify and solve for n:
n^2 + 4n + 4 = n^2 + 2n + 34
2n = 30
n = 15
So the two integers are 15 and 17.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The larger integer is always 1/2 the difference.
34/2 = 17
--> 15 & 17
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