SOLUTION: Find two consecutive positive integers such that the sum of their squares is 113.
Algebra.Com
Question 475430: Find two consecutive positive integers such that the sum of their squares is 113.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
113/2 = 56.5
sqrt(56.5) = about 7.5, the center
--> 7 & 8
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You can do it the hard way:
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