SOLUTION: Find four consecutive integers such that the product of the two larger integers is 22 less than twice the product of the two smaller integers.

SOLUTION: Find four consecutive integers such that the product of the two larger integers is 22 less than twice the product of the two smaller integers.

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Question 473946: Find four consecutive integers such that the product of the two larger integers is 22 less than twice the product of the two smaller integers.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
2(n)(n+1)-22=(n+2)(n+3)
2n2+2n-22=n2+5n+6
n2-3n-28=0
(n-7)(n+4)=0
n=-4 or 7
Throwing out the negative answer, we get the consecutive integers to be 7,8,9,and 10..
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