SOLUTION: The product of two consecutive even integers x and y is 40 less than 20 times their sum. Find the two integers. (Assume x

SOLUTION: The product of two consecutive even integers x and y is 40 less than 20 times their sum. Find the two integers. (Assume x < y.)

Question 469884: The product of two consecutive even integers x and y is 40 less than 20 times their sum. Find the two integers. (Assume x < y.)
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

Let x and (x+2)represent the two consecutive even integers, that is  y = (x+2)

Question states***

x(x+2)= 20[ x +(x+2)] - 40

Solving for x

 x^2 + 2x = 40x 

 x^2 -38x = 0

x(x-38) = 0  0,2  and 38,40 are the two sets of consecutive even integers 



CHECKING our Answer***putting values back into the original EQ

 0 = 0 for x = 0

and for x = 38:

 38*40  = 1520 = 20*78 - 40 = 1520 

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